友情提示:如果本网页打开太慢或显示不完整,请尝试鼠标右键“刷新”本网页!阅读过程发现任何错误请告诉我们,谢谢!! 报告错误
飞读中文网 返回本书目录 我的书架 我的书签 TXT全本下载 进入书吧 加入书签

flying machines-第21章

按键盘上方向键 ← 或 → 可快速上下翻页,按键盘上的 Enter 键可回到本书目录页,按键盘上方向键 ↑ 可回到本页顶部!
————未阅读完?加入书签已便下次继续阅读!




horsepower。 For an average modern flying machine;

with a total load; machine and passengers; of 1;200

pounds; and equipped with a 50…horsepower engine; 50

miles an hour is the maximum。 Here we have the equivalent

of exactly 24 pounds per horsepower。 Why this

great difference?



No less an authority than Mr。 Octave Chanute answers

the question in a plain; easily understood manner。 He

says:



〃In the case of an automobile the ground furnishes a

stable support; in the case of a flying machine the engine

must furnish the support and also velocity by which the

apparatus is sustained in the air。〃



Pressure of the Wind。



Air pressure is a big factor in the matter of aeroplane

horsepower。 Allowing that a dead calm exists; a body

moving in the atmosphere creates more or less resistance。

The faster it moves; the greater is this resistance。

Moving at the rate of 60 miles an hour the resistance;

or wind pressure; is approximately 50 pounds to the

square foot of surface presented。 If the moving object

is advancing at a right angle to the wind the following

table will give the horsepower effect of the resistance

per square foot of surface at various speeds。



                  Horse Power

Miles per Hour    per sq。 foot

10             0。013

15             0 044

20             0。105

25             0。205

30             0。354

40             0。84

50             1。64

60             2。83

80             6。72

100            13。12



While the pressure per square foot at 60 miles an hour;

is only 1。64 horsepower; at 100 miles; less than double

the speed; it has increased to 13。12 horsepower; or exactly

eight times as much。 In other words the pressure

of the wind increases with the square of the velocity。

Wind at 10 miles an hour has four times more pressure

than wind at 5 miles an hour。



How to Determine Upon Power。



This element of air resistance must be taken into consideration

in determining the engine horsepower required。

When the machine is under headway sufficient

to raise it from the ground (about 20 miles an hour);

each square foot of surface resistance; will require nearly

nine…tenths of a horsepower to overcome the wind pressure;

and propel the machine through the air。 As

shown in the table the ratio of power required increases

rapidly as the speed increases until at 60 miles an hour

approximately 3 horsepower is needed。



In a machine like the Curtiss the area of wind…exposed

surface is about 15 square feet。 On the basis of this

resistance moving the machine at 40 miles an hour would

require 12 horsepower。 This computation covers only

the machine's power to overcome resistance。 It does

not cover the power exerted in propelling the machine

forward after the air pressure is overcome。 To meet

this important requirement Mr。 Curtiss finds it necessary

to use a 50…horsepower engine。 Of this power; as

has been already stated; 12 horsepower is consumed

in meeting the wind pressure; leaving 38 horsepower

for the purpose of making progress。



The flying machine must move faster than the air to

which it is opposed。 Unless it does this there can be no

direct progress。 If the two forces are equal there is no

straight…ahead advancement。 Take; for sake of illustration;

a case in which an aeroplane; which has developed a

speed of 30 miles an hour; meets a wind velocity of

equal force moving in an opposite direction。 What is

the result? There can be no advance because it is a

contest between two evenly matched forces。 The aeroplane

stands still。 The only way to get out of the difficulty

is for the operator to wait for more favorable conditions;

or bring his machine to the ground in the usual

manner by manipulation of the control system。



Take another case。 An aeroplane; capable of making

50 miles an hour in a calm; is met by a head wind of 25

miles an hour。 How much progress does the aeroplane

make? Obviously it is 25 miles an hour over the ground。



Put the proposition in still another way。 If the wind

is blowing harder than it is possible for the engine power

to overcome; the machine will be forced backward。



Wind Pressure a Necessity。



While all this is true; the fact remains that wind

pressure; up to a certain stage; is an absolute necessity

in aerial navigation。 The atmosphere itself has very

little real supporting power; especially if inactive。 If

a body heavier than air is to remain afloat it must move

rapidly while in suspension。



One of the best illustrations of this is to be found in

skating over thin ice。 Every school boy knows that if

he moves with speed he may skate or glide in safety

across a thin sheet of ice that would not begin to bear

his weight if he were standing still。 Exactly the same

proposition obtains in the case of the flying machine。



The non…technical reason why the support of the machine

becomes easier as the speed increases is that the

sustaining power of the atmosphere increases with the

resistance; and the speed with which the object is moving

increases this resistance。 With a velocity of 12 miles

an hour the weight of the machine is practically reduced

by 230 pounds。 Thus; if under a condition of absolute

calm it were possible to sustain a weight of 770 pounds;

the same atmosphere would sustain a weight of 1;000

pounds moving at a speed of 12 miles an hour。 This

sustaining power increases rapidly as the speed increases。

While at 12 miles the sustaining power is figured at

230 pounds; at 24 miles it is four times as great; or 920

pounds。



Supporting Area of Birds。



One of the things which all producing aviators seek

to copy is the motive power of birds; particularly in their

relation to the area of support。 Close investigation has

established the fact that the larger the bird the less is

the relative area of support required to secure a given

result。 This is shown in the following table:



                                              Supporting

             Weight       Surface       Horse      area

Bird         in lbs。     in sq。 feet   power     per lb。

Pigeon         1。00      0。7           0。012     0。7

Wild Goose     9。00      2。65          0。026     0。2833

Buzzard        5。00      5。03          0。015     1。06

Condor        17。00      9。85          0。043     0。57



So far as known the condor is the largest of modern

birds。 It has a wing stretch of 10 feet from tip to tip; a

supporting area of about 10 square feet; and weighs 17

pounds。 It。 is capable of exerting perhaps 1…30 horsepower。

(These figures are; of course; approximate。)

Comparing the condor with the buzzard with a wing

stretch of 6 feet; supporting area of 5 square feet; and a

little over 1…100 horsepower; it may be seen that; broadly

speaking; the larger the bird the less surface area (relatively)

is needed for its support in the air。



Comparison With Aeroplanes。



If we compare the bird figures wit
返回目录 上一页 下一页 回到顶部 0 0
未阅读完?加入书签已便下次继续阅读!
温馨提示: 温看小说的同时发表评论,说出自己的看法和其它小伙伴们分享也不错哦!发表书评还可以获得积分和经验奖励,认真写原创书评 被采纳为精评可以获得大量金币、积分和经验奖励哦!